Talk:Geometry:WAXS 3D
Revision as of 16:16, 13 January 2016 by KevinYager (talk | contribs) (→Check of Total Magnitude #2: Doesn't work)
Check of Total Magnitude #1: Doesn't work
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} \left ( \frac{q}{k} \right )^2 d^{\prime 2} & = \begin{alignat}{2} [ & \left( x \cos \phi_g -\sin \phi_g ( d \cos \theta_g - z \sin \theta_g ) \right)^2 \\ & + \left( x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) - d^{\prime} \right)^2 \\ & + \left( d \sin \theta_g + z \cos \theta_g \right)^2 ] \end{alignat} \\ & = \begin{alignat}{2} [ & x^2 \cos^2 \phi_g - x \cos \phi_g \sin \phi_g ( d \cos \theta_g - z \sin \theta_g ) + \sin^2 \phi_g ( d \cos \theta_g - z \sin \theta_g )^2 \\ & + x^2 \sin^2 \phi_g + x \sin \phi_g \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) - d^{\prime} x \sin \phi_g \\ & + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g )x \sin \phi_g + \cos^2 \phi_g ( d \cos \theta_g - z \sin \theta_g )^2 - d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \\ & - d^{\prime} x \sin \phi_g - d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) + d^{\prime 2} \\ & + d^2 \sin^2 \theta_g + 2 d \sin \theta_g z \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\ & = \begin{alignat}{2} [ & x^2 \cos^2 \phi_g - x \cos \phi_g \sin \phi_g ( d \cos \theta_g - z \sin \theta_g ) + \sin^2 \phi_g ( d \cos \theta_g - z \sin \theta_g )^2 \\ & + x^2 \sin^2 \phi_g + 2 x \sin \phi_g \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) - 2 d^{\prime} x \sin \phi_g \\ & + \cos^2 \phi_g ( d \cos \theta_g - z \sin \theta_g )^2 - 2 d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) + d^{\prime 2} \\ & + d^2 \sin^2 \theta_g + 2 d \sin \theta_g z \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\ & = \begin{alignat}{2} [ & x^2 - x \sin \phi_g \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) + ( d \cos \theta_g - z \sin \theta_g )^2 \\ & + 2 x \sin \phi_g \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) - 2 d^{\prime} x \sin \phi_g \\ & - 2 d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) + d^{\prime 2} \\ & + d^2 \sin^2 \theta_g + 2 d z \sin \theta_g \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\ & = \begin{alignat}{2} [ & x^2 + d^2 \cos^2 \theta_g - 2 dz \cos \theta_g \sin \theta_g + z^2 \sin^2 \theta_g \\ & + ( - x \sin \phi_g \cos \phi_g + 2 x \sin \phi_g \cos \phi_g - 2 d^{\prime} \cos \phi_g )( d \cos \theta_g - z \sin \theta_g ) \\ & - 2 d^{\prime} x \sin \phi_g \\ & + d^{\prime 2} \\ & + d^2 \sin^2 \theta_g + 2 d z \sin \theta_g \cos \theta_g + z^2 \cos^2 \theta_g ] \end{alignat} \\ & = \begin{alignat}{2} [ & d^{\prime 2} + x^2 + d^2 + z^2 - 2 dz \cos \theta_g \sin \theta_g \\ & + ( x \sin \phi_g \cos \phi_g - 2 d^{\prime} \cos \phi_g )( d \cos \theta_g - z \sin \theta_g ) \\ & + 2 d z \sin \theta_g \cos \theta_g - 2 d^{\prime} x \sin \phi_g ] \end{alignat} \\ & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g + ( x \sin \phi_g \cos \phi_g - 2 d^{\prime} \cos \phi_g )( d \cos \theta_g - z \sin \theta_g ) \\ & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g + ( x \sin \phi_g - 2 d^{\prime} )\cos \phi_g( d \cos \theta_g - z \sin \theta_g ) \\ & = ? \\ & = ? \\ & = 2 d^{\prime 2} - 2 d^{\prime} x \sin \phi_g + 2 d^{\prime} \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \\ & = 2 d^{\prime} \left( d^{\prime} - x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g ) \right) \\ \left( \frac{q}{k} \right)^2 & = 2 \left( 1 - \frac{x \sin \phi_g + \cos \phi_g ( d \cos \theta_g - z \sin \theta_g )}{d^{\prime} } \right) \end{alignat} }
Check of Total Magnitude #2: Doesn't work
We define:
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{alignat}{2} d^{\prime} & = \sqrt{x^2 + d^2 + z^2} = \| \mathbf{v}_1 \| \\ ( v_{2y} ) & = ( d \cos \theta_g - z \sin \theta_g ) \\ ( v_{2y} )^2 & = ( d \cos \theta_g - z \sin \theta_g )^2 \\ & = d^2 \cos^2 \theta_g - 2dz \cos \theta_g \sin\theta_g + z^2 \sin^2 \theta_g \end{alignat} }
And calculate:
Grouping and rearranging:
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{alignedat}{2}\left({\frac {q}{k}}\right)^{2}d^{\prime 2}&={\begin{alignedat}{2}[&x^{2}+(v_{2y})^{2}\\&-2d^{\prime }x\sin \phi _{g}\\&-2d^{\prime }\cos \phi _{g}(v_{2y})\\&+d^{\prime 2}\\&+d^{2}\sin ^{2}\theta _{g}+2dz\sin \theta _{g}\cos \theta _{g}+z^{2}\cos ^{2}\theta _{g}]\end{alignedat}}\\&={\begin{alignedat}{2}[&d^{\prime 2}+x^{2}+(d^{2}\cos ^{2}\theta _{g}-2dz\cos \theta _{g}\sin \theta _{g}+z^{2}\sin ^{2}\theta _{g})\\&-2d^{\prime }x\sin \phi _{g}-2d^{\prime }\cos \phi _{g}(v_{2y})\\&+d^{2}\sin ^{2}\theta _{g}+2dz\sin \theta _{g}\cos \theta _{g}+z^{2}\cos ^{2}\theta _{g}]\end{alignedat}}\\&={\begin{alignedat}{2}[&d^{\prime 2}+x^{2}+d^{2}+z^{2}\\&-2d^{\prime }x\sin \phi _{g}-2d^{\prime }\cos \phi _{g}(v_{2y})]\end{alignedat}}\\&=2d^{\prime 2}-2d^{\prime }x\sin \phi _{g}-2d^{\prime }\cos \phi _{g}(v_{2y})\\&=?\\&=?\\&=?\\&=2d^{\prime 2}-2d^{\prime }x\sin \phi _{g}+2d^{\prime }\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\\&=2d^{\prime }\left(d^{\prime }-x\sin \phi _{g}+\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})\right)\\\left({\frac {q}{k}}\right)^{2}&=2\left(1-{\frac {x\sin \phi _{g}+\cos \phi _{g}(d\cos \theta _{g}-z\sin \theta _{g})}{d^{\prime }}}\right)\end{alignedat}}}